Question

An aluminum kettle weighs 1.05 kg.

(a) What is the heat capacity of the kettle?

(b) How much heat is required to increase the temperature of this kettle from 23.0 °C to 99.0 °C?

(c) How much heat is required to heat this kettle from 23.0 °C to 99.0 °C if it contains 1.25 L of water (density of 0.997 g/mL and a specific heat of 4.184 J/g °C)?

Answer 1

Answer a) as the Kettle is made of aluminium, the heat and Capacity of aluminium is 0.8977 b) - = mx Cpx oT Yki mx Gp x [ T2-T] x 1050 0.8933 m = 1.05 k3= 10509 cp = 0.89% 349"C T2 = 99.0 °C (99-23) col = 23.0°C 2 = 1250 mL 9x= 941.85 x 76 J + 9x = $1580. 6 J c) q = quater +qx density (d) - 0.997g/ent volume lv) = 1.25L - sy, mass of water cm) = dxy = 12506t3x0.9THAT = 1246.25 g Cu = mx C x 4T = 1246.25 % x 4.184(1) (99-23368 = 396287.56 I 9 = q w + Qk = 396287.56 J + 71580.6 J = 467868.16 J