Question

Convert a decimal fractional number 34/5 to its binary equivalent using a program to  evaluate the bits of the fractional part for at least upto the second repeating block.

i have written some code in python however it is not getting an output at all, so either fixing the code or writing another one would be beyond helpful

def binary(n,k):
n = 8.6
k = 3
#'n' is the fractional number
#'k' is the number of bits up to the loop ;
integral = int(n)
fraction = n-integral

b = '.'
while(k):
fraction = fraction * 2
fra_num = int(fraction)
if (frac_num == 1):
fraction = fraction - frac_num
b = b + '1'
else:
b = b + '0'
k = k - 1
return b

Answer 1

def Binary(num, k_prec) :

    binary = ""

    Integral = int(num)  

    fractional = num - Integral

    while (Integral) :

        rem = Integral % 2

        binary += str(rem);

        Integral //= 2

    binary = binary[ : : -1]

    binary += '.'

    while (k_prec) :  

        fractional *= 2

        fract_bit = int(fractional)

        if (fract_bit == 1) :

            fractional -= fract_bit

            binary += '1'

        else :

            binary += '0'

        k_prec -= 1

    return binary

if __name__ == "__main__" :

    n = 8.6

    k = 8

    print(Binary(n, k))

Output:

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