Question

20. The weights of steers in a herd are distributed normally. The standard deviation is 300 lbs and the mean steer weight is 1300 lbs. Find the probability that the weight of a randomly selected steer is less than 1476 lbs. Round your answer to four decimal places.

Answer 1

Solution :

Given that ,

mean = $\mu$ = 1300

standard deviation = $\sigma$ = 300

P(x < 1476) = P[(x - $\mu$ ) / $\sigma$ < (1476 - 1300) / 300]

= P(z < 0.59)

= 0.7224

Probability = 0.7224