NaOH, Br CH,NH + CO2 H20 H₃C' `NH₂ Amides can be converted into primary amines with the loss of a single carbon atom by the Hofmann rearrangement base Draw curved arrows to show the movement of electrons in this step of the mechanism Arrow.pushing Instructions Br H3C N Submit Answer Try Another Version 1 Hemattempt remaining
CH CH2 CH-NH, CI+NaOH + CH3 — CН— СH, — CH2 CH2 NH, CI + NaOH
Classify each of the following organic reactions. Addition CH3-CH2-CH-CH3 – CH3-CH2-CH=CH2 + HCI CH3-C-O-CH3 + CH3-NH-CH3-C-NH-CH3 + CH2-OH CH3-CH2-CH2-OH + HBr -- CH3-CH2-CH2-Br + H20 Elimination OH CH2-CH + HCN – CH3-CH-CN CH3-CH=CH-CH3 + HBr + CH3-CH-CH2-CH3 Br Substitution CH3-CH2-CH2-CH3 + Cl2 → CH-CH2-CH2-CH3 + HCI СІ CH3-CH=CH-CH3 + Cl2 - CH3-CH-CH-CH3 CICI Reset
Name all of the products of the following reaction. (6 points) CH3-CH2-C-NH-CH3 + NaOH - WH-CH HTML Editora В І ОА IX E XXX, E V 6V TTTT 12pt Paragraph
+ C) NH H2N CO2H 2 moles NaOH NH3 н. D) CH,CH(CH3)2 ОН H2N
+ C) NH H2N CO2H 2 moles NaOH NH3 н. D) CH,CH(CH3)2 ОН H2N
b) CH, CH2 CH CH Br + SH — CHZ CH3 CH, CH, CH, Br + SH" — c) (polar protic solvents) CH, Br + (CH3)3N CH, Br + (CH3)3P - — d) CH, I + CN- - DMF CHZI + CNC CH3CH20H e) CH I + OH- - CHZI + CH, CO2- (6) 14. Place 1º, 2º, 3º and Methyl carbocations in order from least stable to most stable. What factor(s) account for the stability of the most stable...
6. The structure of 2-ethylbenzamide is C-NH CH-CH3 C-NH-CH-CH NH-CH O CH,-CH C-NH2 do CH-CH:
A) 1) NaOH 2) PhCH Br 3) NaOH Br 4) 5) H307, heat B) 1) NaOE 2) PhCH2Br 3) NaOET Br 5) H30-, heat C) 1) NaOET 2) Bromo benzene 3) NaOEt Br 4) Review of Skills - Skill Builder 21.05 Choose the correct order of reagents for performing the following transformation. 1) COH Eto OEU 2) 3) 4) 5)
Identify CH3 i think its CH₃NH C CH3 t the Secondary amines. - NHCH3 CH₃ CH3 NCH3 CH₃CH2NH2 other options are -NH2 The Amines that can be acylated are CH3 definetely NOT → - @ (В CH3 H3C-C- Nha CH3