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Please show all work!7) (10 point) (Binomial) According to the 2018 Utah Dept of Health immunization report, approximately 5% of kindergarten stud

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Answer #1

probability of clamming immunization exemption by a student= 0.05

now, let x= number of students having exemption  p(x)=0.05*e^{-x}; x=0,1,2,....20

likelihood function

L= \prod_{x=0}^{20}p(x)\\ L=(0.05)^{20}*e^{\sum_{x=0}^{20}x}\\ L=(0.05)^{20}*e^{\sum_{x=0}^{20}x}\\

Likehood that no child has received an exemption

= (0.05)^{20}

Likehood that atleast one child has received an exemption

=(0.05)^{20}(1+e)

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