Question

Consider the filter circuit (Figure 1) with R=500 N and C ==uF. Learning Goal: To understand how to find the transfer function of a filter circuit and to be able to draw the asymptotes of the Bode magnitude and phase diagrams Bode plots are used to display the amplitude and phase of a transfer function. The amplitude is typically displayed by showing the magnitude of the transfer function on the vertical axis and the frequency on the horizontal axis using a log-log scale. The Bode plot for the phase typically shows the phase angle on the vertical axis and only uses a log scale for the horizontal frequency axis. Consider the transfer function for a generalized first-order lowpass filter, H ) = The magnitude of this function in decibels is given by Part A Find the value of fe required to express the transfer function of the example circuit in the form Express your answer in hertz to three significant digits. View Available Hint(s) H() dB = -10 log 1+ 10 ALP u vec R o B ? fB = From this form, the asymptotic behavior of the magnitude of the transfer function in decibels can be inferred. For f <fB, the magnitude is H fldB ~ 0, which is a horizontal line through the origin. For f f , the magnitude is H(flde -20 log(f/fb), which is a line with slope -20 through the point (fB,0). This point is the intersection of the two asymptotes. The frequency fb is known as the corner frequency or the break frequency, frequencies above fb are blocked by the filter Submit Part B Complete previous part(s) Figure < 1 of 1 Part C Complete previous part(s) Provide Feedback Ov. ct Von

Answer 1

FB is the Colnee freeley se ENRC for frasa soot fetizo Tig = 1000 Hz RS Scanned with CamScanner