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X 4.5.13 In a certain country, the true probability of a baby being a boy is 0.537. Among the next four randomly selected bir
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Answer #1

\small \mathbf{Solution}

given : n 4, P(girl) = 0.537, p(boy) 1-p(girl) 1-0.5370.463

q(not boy) p(girl) = 0.537

formula P(X = r) C p * q n-T where, TC r!(n-r

Pat least one of them is boy) P(X > 1]

P(X1) 1- P(X< 1)

P(X1) 1- P(X = 0)

P(X 1) 1- {C 0.4630 0.537 10

4! P(X 1) 1 O! (4-0*0.4630 0.5374-0

4! 0.4630 0.5374-0 P(X 1) 1 O!4!

P(X 2 1) 1 {1 1 0.537 1

\small P(X\geq 1)=1-\left \{ 0.083 \right \}

P(X10.917

. The probability is 0.917

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