Kc = 1.80 × 10^-4 (given)
Temperature(T) = 298 k (given)
The equilibrium concentration of H2S (Kp) = ?
For a gas phase reaction,we know Kp = Kc(RT)^∆n
Where ∆n = no. Of moles of gaseous product - no. of moles of gaseous reactants.
Hence from given reaction, ∆n = (1+ 1) - 0
= 2 - 0 = 2
Hence Kp = 1.80 × 10^-4 (8. 314 × 298)^2
(we know R = 8.314 J/k/mol)
= 1.80 × 10^-4 (2477.572)^2
= 1.80 × 10^-4 (61.3 × 10^5)
= 1.80 × 10^-4 × 61.3 × 10^5
= 110.34 × 10
= 1.10 × 10^3
Hence, Equilibrium concentration of H2S (Kp) = 1.10 × 10^3 M
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