%Matlab script to input the value of x and calculate the value
of exp(x)
% to a precision of 6 decimal places
format compact;
% input of x
x = input('Enter the value of x for calculation of exp(x) :
');
n = 0; % set n=0
% set initial approx value to 0
approx = 0;
% set actual value to exp(x) % actual e^x value
actual = exp(x);
% calculate the absolute difference between the calculateed and
approximate
% value
eps = abs(approx-actual);
% loop that continues till the approx value matched the actual
value upto 6
% decimal places
while eps > 10^-7
% calculate approx for (n+1)th term
approx = approx + (x^n/factorial(n));
n = n+1; % increment n
% calculate the difference
eps = abs(approx-actual);
end
% display the approximate value upto 6 decimal places
fprintf('The approximate value of e^x is %.6f \n',approx);
%end of script
Output:
Solve the following problem in MATLAB. Use format compact for all work to suppress extra lines....
MATLAB
Use the Taylor series cos(x)-1-to compute cos(x) to four decimal places (by comparing the value with the matlab built-in function for cos). How many iterations does it take to get to 4- decimal place agreement? (hint: help factorial) 2! 4! 6!
MATLAB ONLY!! PLEASE WRITE IN COMPUTER SO I CAN COPY
PASTE!!! ANSWER COMPLETELY, USE FOR LOOPS.
THE PROGRAM TO BE MODIFIED IS THE NEXT ONE:
clc
clear
% Approximate the value of e ^ x using the Taylor Series
x = input( 'Enter the value of x for e^x. x = ' );
t = input( 'Enter the amount of desired terms. t = ' );
i = 1;
e_taylor = 0; % initializing the variable for the
accumulator
while...
Please use matlab to solve the question.
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