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5. (9 Points) A 3.75 L sample of gas...
A 1.55-mol sample of nitrogen gas is maintained in a 0.730-L container at 292 K. Calculate...
A 1.55-mol sample of nitrogen gas is maintained in a 0.730-L container at 292 K. Calculate the pressure of the gas using both the ideal gas law and the van der Waals equation (van der Waals constants for N2 are a = 1.39 L2atm/mol2 and b = 3.91×10-2 L/mol). Pideal gas equation = ______ atm Pvan der Waals =_____ atm
The observed pressure of a 2.963-mole sample of Kr(g) in a 9.450-L container is 1.782 atm....
The observed pressure of a 2.963-mole sample of Kr(g) in a 9.450-L container is 1.782 atm. Use the van der Waals equation to determine the pressure if the gas were behaving ideally. Kr(s) = 2.32 atm. L2 mol Our(s) = Ideal pressure atm
According to the ideal gas law, a 10.65 mol sample of krypton gas in a 0.8201...
According to the ideal gas law, a 10.65 mol sample of krypton gas in a 0.8201 L container at 496.1 K should exert a pressure of 528.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Kr gas, a 2.318 LPatm/mol? and b 3.978x102 L/mol. Pideal-Poan der Woals Percent difference x 100 Pnal+Pn der Waals 2 %
According to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm
Hint: % difference = 100×(P ideal - Pvan der Waals) / P idealAccording to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Ar gas, a =1.345L2 atm/mol2 and b = 3.219×10-2 L/mol.
A 200.5 g sample of methane gas has a volume of 25 L at 25 degrees...
A 200.5 g sample of methane gas has a volume of 25 L at 25 degrees celcius. Calculate the pressure using the ideal gas law. Calculate the corrected pressure using the van der waal's equation (a=2.25 atm L2 mol-2; b= 0.0428 L*mol-1)
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0...
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
According to the ideal gas law, a 0.9832 mol sample of carbon dioxide gas in a...
According to the ideal gas law, a 0.9832 mol sample of carbon dioxide gas in a 1.975 L container at 271.4 K should exert a pressure of 11.09 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For CO2 gas, a = 3.592 L'atm/mol and b=4.267x102 L/mol. Hint: % difference = 100*(P ideal - Pvan der Waals)/P ideal
A 9.083 mol sample of methane gas is maintained in a 0.8377 L container at 304.9...
A 9.083 mol sample of methane gas is maintained in a 0.8377 L container at 304.9 K. What is the pressure in atm calculated using the van der Waals' equation for CH4 gas under these conditions? For CH4, a = 2.253 L^2atm/mol^2 and b = 4.278 x 10^-2 L/mol.
According to the ideal gas law, a 0.9935 mol sample of krypton gas in a 1.258...
According to the ideal gas law, a 0.9935 mol sample of krypton gas in a 1.258 L container at 265.4 K should exert a pressure of 17.20 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Kr gas, a - 2.318 L'atm/mol- and b= 3.978*10-2 L/mol. Hint: % difference = 100*(P ideal - Pvan der Waals) /P ideal
A 10.74 mol sample of oxygen gas is maintained in a 0.8354 L container at 296.1...
A 10.74 mol sample of oxygen gas is maintained in a 0.8354 L container at 296.1 K. What is the pressure in atm calculated using the van der Waals' equation for O2 gas under these conditions? For 02, a = 1.360 Latm/mo12 and b = 3.183x10-2 L/mol. atm
The observed pressure of a 2.963-mole sample of Kr(g) in a 9.450-L container is 1.782 atm. Use the van der Waals equation to determine the pressure if the gas were behaving ideally. Kr(s) = 2.32 atm. L2 mol Our(s) = Ideal pressure atm
According to the ideal gas law, a 10.65 mol sample of krypton gas in a 0.8201 L container at 496.1 K should exert a pressure of 528.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Kr gas, a 2.318 LPatm/mol? and b 3.978x102 L/mol. Pideal-Poan der Woals Percent difference x 100 Pnal+Pn der Waals 2 %
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
According to the ideal gas law, a 0.9832 mol sample of carbon dioxide gas in a 1.975 L container at 271.4 K should exert a pressure of 11.09 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For CO2 gas, a = 3.592 L'atm/mol and b=4.267x102 L/mol. Hint: % difference = 100*(P ideal - Pvan der Waals)/P ideal
According to the ideal gas law, a 0.9935 mol sample of krypton gas in a 1.258 L container at 265.4 K should exert a pressure of 17.20 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Kr gas, a - 2.318 L'atm/mol- and b= 3.978*10-2 L/mol. Hint: % difference = 100*(P ideal - Pvan der Waals) /P ideal
A 10.74 mol sample of oxygen gas is maintained in a 0.8354 L container at 296.1 K. What is the pressure in atm calculated using the van der Waals' equation for O2 gas under these conditions? For 02, a = 1.360 Latm/mo12 and b = 3.183x10-2 L/mol. atm
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