Homework Answers
5.
Rollers = RR, Rr
Non rollers = rr
Bob = Rr (because his mother was non roller, rr, so he cant be RR)
Mother = rr
Bob wife = rr
Rr × rr
| Gametes | r |
| R | Rr (roller) |
| r | rr (non roller) |
PR - 1 (roller) : 1 (non roller)
6.
Black = BB, Bb
White = bb
BB × Bb
| Gametes | B |
| B | BB (black) |
| b | Bb (black) |
All will be black.
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5. Tongue rolling is dominant. Bo her tongue. What are the genotypes children will be tongue...
i need this quick for tongue rolling (Th)is dominant over the allee for not being able...
i need this quick
for tongue rolling (Th)is dominant over the allee for not being able to roll your an who can roll his tongue marries a woman who cannot. They had 11 2. The allele tongue a (t). A m gue children, 6 of whom could roll their tongues, and 5 of whom could not. a. What are the phenotvpes of the parents? Father: Mother What are the POSSIBLE genotypes of the parents (hint, the father could have one...
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Directions: For each of the following problems 13-18, 1. List the genotypes of the parents. 2....
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Genetic Problems
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I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
i need this quick
for tongue rolling (Th)is dominant over the allee for not being able to roll your an who can roll his tongue marries a woman who cannot. They had 11 2. The allele tongue a (t). A m gue children, 6 of whom could roll their tongues, and 5 of whom could not. a. What are the phenotvpes of the parents? Father: Mother What are the POSSIBLE genotypes of the parents (hint, the father could have one...
One-Gene Crosses 1. In Drosophila, gray body color is dominant over black body color. By crossing a heterozygous gray-bodied fly with a black-bodied fly, one hundred offspring resulted. How many would be expected to have black bodies? 7 2. Albinism, the lack of pigment, occurs commonly in animals and is always recessive to normal pigmentation. Ten brown and eight albino mice were born to parents which were likewise brown and albino. What are the genotypes of both parents? 3. The...
3) (1.5 pts) Elizabeth is married to John, and they have four children. Elizabeth has a straight nose (recessive) and is able to roll her tongue (dominant). John is also able to roll his tongue, but he has a convex (Roman) nose (dominant). Of their four children. Ellen is just like her father, and Dan is just like his mother. The other children-Anne, who has a convex nose, and Peter, who has a straight nose are unable to roll their...
Directions: For each of the following problems 13-18, 1. List the genotypes of the parents. 2. Diagram and complete a Puonett square 3. Give the phenotype percentages of the offspring. In garden peas, round seed coats (R) is dominant over wrinkled seed coats (r). 14.) What will the results be of a cross between a homozygous dominant male and a recessive female? In peas, yellow color (Y) is dominant to green (y). 15.) What will be the results of a...
Genetic Problems
10. Hemophilia is a sex-linked disorder. A normal woman whose father was hemophiliac marries a man who is not homophiliae What percentage of their son would be would be expected to be hemophiliac? What percentage of their daughters word expected to be hemophiliacs? Again, show your work, using a Punnett Square 11. Given parents with the genotypes AaBbCcDdEe and AaBbccDdEe. what is the probability of them producing offspring with the genotype of AABCDE 12. In humans, widow's peak...
is In guinea pigs, black coat color (B) is dominant to white (b), and rough color (R) dominant to smooth (o). What following crosses a) BBRR x bbrr b) BBrr x bbRR c) Bbrr x bbRr d) BBRr x BbRr e) BbRr x BbRr 2)The presence of one of the Rh antigens on the surface of the red blood cells (Rh+) in humans is produced by a dominant gene R. Th negative cells are produced by the recessive genotype rr....
10. Red green colorblindness is an X-linked recessive disease. That means that it is carried on the X chromosome, so men have just one copy of the gene while women have two. In women, both copies must be the recessive disease allele in order to show the disease phenotype, but because men only have one allele, just one recessive allele causes the disease phenotype. Matt and Kate both have normal vision, but Kate's father is colorblind. Use X for the...
I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
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