Question

5. Iron(III) oxide reacts with carbon monoxide to produce iron and carbon dioxide according to the following reaction: Fe2O3 + 3 CO → 2 Fe + 3 CO2 a) What is the percent yield of iron if 15.0 grams of FE is actually produced by reacting 65.0 of iron(III) oxide? b) What is the percent yield of carbon dioxide if the reaction produces 85.0 grams of carbon dioxide from 75.0 grams of carbon monoxide?

Answer 1

first find the moles and then based on mole ratio of the reactants and products calculate the theoretical yield and percent yield as follows

Feo, + 300 - > 2Fe + 36 a) No.mokes - Mass Molay may for FeO, = 65.09 199.099/med 0.407030 male - IMOl Fe2O₂ - 2molte 9 0.407038 md - -> 0.407038 x2 => Q.814 molae Theoretical yield > 0.814 x 55.8453) 4.5.4629 of Fe percent yeeles - Actual field xlop Theoretical field 5)_15_, X100 = 330% | 45.462 b Moles of co= 75.0g = 2.6776 mols 28.01 Simol - 3 mod co - 3 mol ca 26776 mol =2676mol There folyieht = .6776 x44 5) 1178159 아와 percent yield - A.Y X IOD = 85 x 100 72.15 270 117.815 Thay