Question

Having obtained the volume of a flask (25.001 mL), the student then emptied the flask and dried it. The mass of the empty stoppered flask was 25.710 g. To the empty flask they added pieces of a metal until the flask was about three-fourths full. The student weighed the stoppered flask and its metal contents and found that the mass was 162.071 g. They then filled the flask with water, stoppered it, and obtained a total mass of 167.932 g for the flask, stopper, metal, and water. Find the density of the metal. a. To find the density of the metal we need to know its mass and volume. We can easily obtain its mass by the method of differences: Mass of metal = g b. To determine the volume of metal, we note that the volume of the flask must equal the volume of the metal plus the volume of water in the filled flask containing both metal and water. If we can find the volume of water, we can obtain the volume of metal by the method of differences. To obtain the volume of the water we first calculate its mass: Mass of water = Mass of (flask + stopper + metal + water) - Mass of (flask + stopper + metal) Mass of water = g The volume of water is found from its density (0.9975 g/mL). Note that 1 mL = 1 cm". Volume of water = C m L c. From the volume of the water, we calculate the volume of metal: Volume of metal = volume of flask - volume of water Volume of metal = mL From the mass and volume of metal, we find the density, using the equation below: mass Density = volume Density of metal = [ g/mL

Answer 1

e have given, volume ofthe fask 25. 0ol mL Mars of empty sto ppered flark = 25.710 mete!)= 162.071 Mars Mars Jc ned fo Know anars k voiume a. To find fhe derkity of meta Mass of emþty Mass of metal = Mars oj (flask 4 Atopper+ mctal) -- btrppired fla^K 25.710) Mas of metai (162.071 Mas o mtal b. Ma of Water- Mar of (flaskt strppartmutal+ Water) achal) df (laskttpper t -Mays The une water i^ found firm iM denkihy Co.99459/mL) ater Density water MAM o.9375 mL e. volume nctni Volume f flask - volume df Water (25. ooi - 5.g76) mL 19. 125 mLL Mass of ntad vafum netal 136.3619 19.125 mL Dentity net 7.13 9/mL