Homework Answers
Solution :
Given mean =1.8
Standard deviation =0.2
a)P(X>1.95) =1-P((x-mu)/s - (1.95-1.8)/0.2)
= 1 - P(Z<0.75)
= 1- 0.7733726
= 0.2266274 = 0.2266
The probability is 0.2266
b)
P( 1.95 < X < 2.35 )
=P((1.95-1.8)/0.2 - (x-mu) /s-(2.35-1.8)/0.2)
=P( 0.75<Z<2.75)
=P(Z<2.75)-P(Z<0.75)
=0.9970202 - 0.7733726
=0.2236476 = 0.2236
The probability is 0.2236
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