Compound | MW | equivalents | mmol | g | density | mL |
---|---|---|---|---|---|---|
Sulfuric Acid (18 M) | XXX | XXX | XXX | 1.711 | ||
methyl benzoate | 0.820 | |||||
sulfuric acid (18 M) | XXX | XXX | XXX | 0.546 | ||
nitric acid | XXX | XXX | XXX | 0.560 |
1. Complete the following table: (hint keep track of your units)
2. What is the theoretical yield for this reaction?
Compound MW equivalents mmol g density mL Sulfuric Acid (18 M) XXX XXX XXX 1.711 methyl...
Prelab Questions. Complete the following table: (hint keep track of your units) MW equivalents mmol ml density XXX 0.920 XXX XXX Compound sulfuric acid (18M) methyl benzoate sulfuric acid 1.088 0.440 XXX XXX XXX 0.460 (18M) XXX 0.440 XXX XXX nitric acid (15.9M) 2. What is the theoretical yield for this reaction? 3. Why is an ice bath employed in the nitration of methyl benzoate? (hint: look at the energy diagram shown on pg 1 of the experiment)
1. Complete the following table: (Hint-Keep track of your units) equivalents mmol density mL Compound sulfuric acid (18M) MW XXX XXX XXX 0.840 2.96 1.04 0.302 benzaldehyde sulfuric acid (18M) nitric acid (15.9M) XXX XXX XXX 0.280 XXX XXX XXX 0.372 2. What is the theoretical yield for this reaction (nitration of benzaldehyde)?
Complete the table for the reaction Compound MW Equivalents mmol g density mL Acetic Acid (glacial) 60.05 1.049 Isopentyl alcohol 88.15 0.810 18 M sulfuric acid XXX XXX XXX XXX 0.022 Low Hond Is Lord +
Complete the table 2. Complete the following table: Compound MW equivalents mmo mL density Acetic acid, conc. 5.84 glacial) Isopentyl 2.92 alcohol Sulfuric (I8M) acid, conc. XXX 0.016 3. Calculate the theoretical yield for the synthesis of isopentyl acetate.
What would be the theoretical yield of reacting methyl benzoate (C₆H₅CO₂CH3) with nitric acid (HNO3) and sulfuric acid (H2SO4), producing methyl m-nitrobenzoate (C6H4CO2CH3NO2)? 6 g methyl benzoate 4 mL nitric acid 4 mL sulfuric acid crude methyl m-nitrobenzoate recovered: 7.260 g pure methyl m-nitrobenzoate recovered: 6.227 g
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all steps. Results: .040 g of methyl m-nitrobenzoate crystals produced 1. Add .30 g of Methyl Benzoate to .6 ml of Sulfuric Acid in a reaction tube 2. Dropwise add a mixture of .2 ml of sulfuric acid and .2ml of nitric acid 3. After 15 min, pour onto 2.5 g of ice in a small beaker 4. Use suction filtration to dry crystals. Wash...
-NITRATION OF Methyl benzoate -addditional information. .( 3.9 g of the product methyl 3-nitrobenzoate for the percentage yield Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
Solution 1 (starting material): 4.0 mL of concentrated sulfuric acid is added to a flask, 2.0 mL of methyl benzoate is then added to the sulfuric acid solution Solution 2 (electrophile, nitronium ion): 2.0 mL of concentrated nitric acid is added to a test tube, followed by 2.0 mL of concentrated sulfuric acid. Add solution 2 to solution 1. Calculate the theoretical yield. concebtration was not given
Question #1 Please Complete the following reagent table: Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4 K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16 bp: 140°C mp: 135°C Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4 K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16...
Et2NH m-toluic acidSOC2m-toluic acid chloride diethyltoluamide MW / Cond volume density 2.2 M in 5% NaOH (aq) 5 mL Theoretical ieso Theoretical ield mass 0.40 8 mmol equiv 1.0 1.5 *4 b) Show calculations to determine the theoretical yield using the amounts of reagents above. (1 point)