Question

java

a. What is printed by the following code? Explain your answer by showing how you computed the values of pos, s1, s2 and 53. String str = "2900 Bedford Ave Brooklyn NY 12230-6843"; int pos = str.indexOf(" ", str.indexOf(" ", 'B') + 1); String si = str.substring(o, pos); System.out.println("pos: + post sl: + sl); pos - str.indexOf("B", pos+1); pos = str.indexOf("B", pos+1); String s2 = str.substring(pos, str. indexOf(" ", pos)): System.out.println("pos: + pos + + s2); String s3 = str.substring(str.lastIndexOf("1")); System.out.println("s3: + S3): 52: pos si pos s2 b. What is printed by the following code? Explain your answer. String sl - "01234"; String s2 = "98765"; String s3 - S2 + sl: for (int i = 0; i < 52.1ength: 1++){ sl - s2.charAt(s2.length() - 1 - 1) + sl; } System.out.println("si: " + sl); System.out.println("s3: " + $3); if (s1 - $3)System.out.println("s1 and s3 are equal"); else System.out.println("sl and s3 are not equal"); s2 sl 11 s3

Answer 1

a.

CODE:

COPY (for copy):

//Main Class
class Abc
{   
   //Main Method
public static void main(String []args){
    //Storing string in str variable
String str = "2900 Bedford Ave Brooklyn NY 12230-6843";
/*
str.indexOf(" ",'B') return value -1 cause 'B' is not an integer
    Therefore, pos = str.indexof(" ", -1 + 1) finds space from position 0
    which is 4. So, pos = 4.
*/
int pos = str.indexOf(" ", str.indexOf(" ",'B') + 1);
//s1 will be string from 0 to 4 of str which is "2900"
String s1 = str.substring(0, pos);
//Output will be "pos: 4 s1: 2900"
System.out.println("pos: " + pos + " s1: " + s1);
/*pos = str.indexOf("B", 4 + 1) will find "B" from position 5 which is
5. So, pos = 5.
       */
pos = str.indexOf("B", pos + 1);
/*pos = str.indexOf("B", 5 + 1) will find "B" from position 6 which is
17. So, pos = 17.
       */
pos = str.indexOf("B", pos + 1);
/*s2 will be string from 17 to str.indexOf(" ", 17) will find space from
position 17 which is 25. So, s2 will be "Brooklyn".
*/
String s2 = str.substring(pos, str.indexOf(" ", pos));
//Output will be "pos: 17 s2: Brooklyn"
System.out.println("pos: " + pos + " s2: " + s2);
/*str.lastIndexOf("1") finds the last position of "1" which is 29. s3
will be 29 to end of string
*/
String s3 = str.substring(str.lastIndexOf("1"));
//Output will be "12230-6843"
System.out.println("s3: " + s3);
   }
}

OUTPUT:

b.

CODE:

CODE (for copy):

//Main Class
class Abc
{   
   //Main Method
public static void main(String []args){
    //Storing string s1 and s2 variable
String s1 = "01234";
String s2 = "98765";
//Concatination of s2 and s1 in s3
String s3 = s2 + s1;
//Loop from 0 to length of s2
for(int i = 0; i < s2.length(); i++){
   //Concatination of s2 letter by letter in s1
   s1 = s2.charAt(s2.length() - i - 1) + s1;
}
//Output will be "9876501234"
System.out.println("s1: " + s1);
//Output will be "9876501234"
System.out.println("s3: " + s3);
//s1 and s3 are same as string but variable are not same
if(s1 == s3)
   System.out.println("s1 and s3 are equal");
else
   System.out.println("s1 and s3 are not equal");
   }
}

OUTPUT:

Please comment for any doubt.