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Trial #1 = 10.2 J of Kinetic Energy Trial #2 = 10.1 J of Kinetic Energy...

Trial #1 = 10.2 J of Kinetic Energy

Trial #2 = 10.1 J of Kinetic Energy

Trial #3 = 9.9 J of Kinetic Energy


From this experiemental data, calculate the approximate spring constant of the plunger, if it is 2.5 cm long and is fully compressed.

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Answer #1

1 m=100 cm 100 Thus 2.5 2.5 cm m 100 -0.025 m Write the expression for kinetic energy K.E Here, k is spring constant, x is le

Case 2 Substitute 10.1J for K.E. in equation (1). K.E 10.1 (0.025) - 32320 Hence, for Trial #2, the value of spring constant

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