Question

The figure gives the speed v versus time t for a 0.909 kg object of radius 9.50 cm that rolls smoothly down a 31.6° ramp. What is the rotational inertia of the object?
(S/L) A 0 0.8 1 0.2 0.4 0.6 t(s)

0 0
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Answer #1

Sol:— Given, Mass of object = m = 0.909 kg - Radius of object =R=9.5 cm 1 0= 316 Vimist From the given Vast & T T T (2, 3.5)Q=26= 20 cms2 Now, we know the angulos acceleration [:a=Rox] 1:= der sells ↑ng laro VR SEN ng as o persone Here L- Foro Roter. T- I. F = Frajectoral force D EX R = I x la B UN XR = I x R 3) 1. I = ju ng wrex RX 3R TI = 3 long as Oop² TH= frictiona Cois I = 2 981 (en\64 ) x sin (31-7) – 1 9 7 *(0-909 AG) * (9.5 cm)? I = 12568.84 07 I = 1.2568 kg-m?

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