Question

Electrical subject

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LL 3. Electrostatics (Total points: 14) Two identical small charged spheres, each having a mass of 0.04 kg, hang in equilibrium as shown in the figure. The length of each string is 0.2 m, and the angle is 15.0°. Find the magnitude of the charge on each sphere. (Hint: draw the free body diagram of one charge) 40 09 a 4. DC circuit Calculate the value of the Iro current flowing through the Ro resistance by using Thevenin theorem! Draw the equivalent Thevenin circuit and give the value of Thevenin equivalent voltage source and resistance! Parameters: U=20 V, R=212, R2=1 S2, R3=3 S2, R==2 S2, Rs=4 S2, Ro=2 32 R2 R5 a VIRO ulo CR, R4 R6 R3 b

Answer 1

3) 27 l F Fe a Fe 29 ng ng we know that Efx=0 fe-Tsin o=0 .: Tsino=fe and Efy 0 Tcoso -w-o TLoso=w Druide en by 2 T Sino Fe T como ک) Fe ten o = w But Fe=kQ² Izan and w= .my tan o = K d? (2a7 xing

(2912 ng tono But hee cm fond a from Fig sino- d :: e sino=a 2 Q= (zesino 12 ng tano K .:Q=12l sin of me tone Now e=0.2m, o=150 m=0.04 kg and I= Ž 9x109 4 Itto g=9.800/2 1 &= 1 2x0.25in (15)/ oon kyxq.8 m/j²x ten (15) 9x409 Mm2%e2 suncir = + 353-67 nc But 1102 dl=353.60nc

4) For a giren ckt شما 2 t 2 2 20V b Renove teminal a-b theofor ekt becoms, 41/2= 472 8 4+2 2.33 1 2 = 1:33 20v TH 3 - VTH = Ix2R - 20 But I = -10A Uth=-10x2=-20v and short coraut zov lome. 2-33 Now an is short circuted ru Нет Hence RTH = 2-33 +3=5-332 3 Therfe ekt beans, 5-33 -20 IR6= 5.33 +2 =-2-72 AIRG 20 0 IR 6 = -2.72A

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