Question

An object of mass 3M, moving in the +x direction at speed v0, breaks into two pieces of mass M and 2M as shown in the figure below. ?1= 48.0 and ?2= 33.0, determine the final velocities of the resulting pieces in terms of v0.

?? 2?

1) Determine the x component of the velocity of the smaller piece v1x in terms of v0. (Express your answer to three significant figures.)

2) Determine the y component of the velocity of the smaller piece v1y in terms of v0. (Express your answer to three significant figures.)

3) Determine the x component of the velocity of the larger piece v2x in terms of v0. (Express your answer to three significant figures.)

4) Determine the y component of the velocity of the larger piece v2y in terms of v0. (Express your answer to three significant figures.)

Answer 1

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Momentum before collision = Momentum after collision. 3MV_0 i = 2MV_2 cos 33 degree i + 2MV_2 sin 33 degree j + MV_1 cos 48 degree i - MV_2 sin 48 degree j comparing component, 2V_2 cos 33 degree + V_1 cos 48 degree = 3V_0 (1) 2V_2 sin 33 degree - V_2 sin 48 degree = 11 solving (1) and (11), V_1 = 1.654 V_0, V_2 = 1.1286a V_1x = V_1 cos theta_1 = V_1 cos 48 degree = 1.1067 m/s V_1y = -V-1 sin theta_1 = -1.23 m/s V_2x = V_2 cos 33 degree = 0.9465 m/s V_2y = V_2 sin 33 degree = 0.61467 m/s