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6.19. A two-phase system of liquid water and water vapor in equilibrium at 8000 kPa con sists of equal volumes of liquid and

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Answer #1

Since it is given in the question the water and water vapor are in equilibrium, the water vapor will be in saturated form.

So from the steam table for saturated steam at 8000 kPa (8 MPa ),

The total enthalpy Ht = 2758.611 kJ/kg

The total entropy St = 5.745 kJ/ kg . K

This is the image of the saturated steam table at that particular pressure,

275 250 85 | 5.9418 6.4117 6.9004 7.4380 7.9928 0.001317 0.001332 0.00 1348 0.00 1366 0.00 1384 0.03279 0.03017 0.02777 0.025

The first column is temperature, the second column is pressure, fourth last column is total enthalpy and the last column is the total entropy.

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