Question

LINEWEAVER-BURK plot 1. You perform the hydrolysis reaction as required in the lab experiment, and the final reading on your blood glucose meter for one of your samples is 385 mg/dL. You need your data to be in units of mm (millimolar, which is millimoles per liter, abbreviated as mmol/L). Show, in a step-by-step conversion, how you would convert 385 mg/dL to the proper answer in mM. 385 mg dlº= ?mm immoles 2. Assuming that the reaction occurred over a 30 minute time period, what is the rate of the reaction in mM/min?

Answer 1

Reading in blood glucose meter is 385 mg/dL

= 385 × ( 10^-3 g/10^-1 L)

= 3.85 g/L

Now molecular weight of glucose=180

So no of moles of glucose per litre = (3.85/180)

=0.0214

So concentration of glucose = 0.0214 M

= 0.0214 × 10³ mM

= 21.4 mM

2. As the reaction has occured over 30 minutes so rate of reaction

= Change in concentration/ time

= (21.4/30)mM/min

=0.7133 mM/min.