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How many liters of NH3 can be produced at 22 atm and 24 C from a 98 g sample of nitrogen gas and an excess of hydrogen gas?
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Answer #1

N2 + 3H₂ → 2NH3 moles of Na= mass M.U 989 = 2891nd 3.5 and moly of NH3 = 2x3.5 --7 mol volume of NH3 = mols & gas const. x TeN2 + 3H₂ → 2NH3 moles of Na= mass M.U 989 = 2891nd 3.5 and moly of NH3 = 2x3.5 --7 mol volume of NH3 = mols & gas const. x Te

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