Question

7. A U-tube is filled with water until the liquid level is 29 cm above the bottom of the tube. An oil of specific gravity 0.80 is now poured into one arm of the U-tube until the level of the water in the other am, of the tube is 34 cm above the bottom of the tube. Find the level of the oil-water and oil-air interfaces In the other arm of the tube. cm (oil-water) cm (oil-air)

Answer 1

From the point of the interface oil-water:

$\rho_wgh_w = \rho g(h_w+h)$

$h_w\frac{\rho_w}{\rho} = (h_w+h)$

h (oil-air) = 42.5 cm

h(oil-water) = 42.5-29 = 13.5 cm