Using the equation,
p = p0 + ρgh
pi = pressure at interface of the two liquids.
pA = atmospheric pressure. ρ1 = density of oil. ρ2 = density of unknown liquid. h1 = 12cm. h2 = 5cm.
At the interface between the oil and liquid the pressure will be the same as the pressure 12 - 5 = 7cm below the surface:
pA + ρ2g(h1 - h2) = pA + ρ1gh1
ρ2 = ρ1h1 / (h1 - h2) = [800kg/m^3][12/7] = 1371.4285 kg/m^3
Second question is incomplete, as per HOMEWORKLIB POLICY I have solved one complete question.
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