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ELET 4501 Test #2 2. One Kilo Byte is bytes One Byte is _brts. 4. One...
4. (20%) PC1 sends a 1,500 octet datagram (20-byte header and 1,480 bytes of data, IP...
4. (20%) PC1 sends a 1,500 octet datagram (20-byte header and 1,480 bytes of data, IP ID = 677 to PC2 through the routers R1 and R2. The corresponding MTUs are given in the following diagram. Please show the information about IP packet identification, total packet length, IP flag bit Mand fragment offset in the IP header of each fragmented IP packet. R1 R2 MTU=1500 bytes MTU=1500 bytes PC1 MTU=500 bytes PC2 Fragment #1 Fragment #2 Fragment #2 Fragment ID...
Suppose you have a byte-addressable virtual address memory system with 8 virtual pages of 64 bytes each
Suppose you have a byte-addressable virtual address memory system with 8 virtual pages of 64 bytes each, and 4-page frames. Assuming the following page table, answer the questions below: Page #Frame #Valid Bit0111312-03014215-06-07-0a) How many bits are in a virtual address? b) How many bits are in a physical address? c) What physical address corresponds to the following virtual addresses (if the address causes a page fault, simply indicate this is the case)? 1) Ox00 2) 0x44 3) OxC2 4) 0x80
Please show all work. I do not understand this question. 4. How many GRa are there...
Please show all work. I do not understand this question.
4. How many GRa are there in 9.3 Ci? Table 5. SI prefixes Factor Name Symbol Factor Name Symbol 1024 yotta Y 102 zetta Z 1018 exa E 1015 peta P 1012 tera T 109 giga G 106 mega M 103 kilo k 102 becte, h 101 deka da 10-1 deci d 10-2 centi c 10-3 milli m 10-6 micro u 10-9 vana n 10-12 pica p 10-15 femta f...
A simple paging system has a memory size of 256 bytes and a page size of...
A simple paging system has a memory size of 256 bytes and a page size of 16 bytes. i. What is the size of the page table? ii. How many bits exist for an address, assuming 1-byte incremental addressing? iii. State p and d values (i.e. the page number and the offset). iv. Perform address translation of 64 bytes to physical address space using the page table below. 0 8 1 6 2 3 3 11 4 7
A simple paging system has a memory size of 256 bytes and a page size of...
A simple paging system has a memory size of 256 bytes and a page size of 16 bytes. i. What is the size of the page table? ii. How many bits exist for an address, assuming 1-byte incremental addressing? iii. State p and d values (i.e. the page number and the offset). iv. Perform address translation of 64 bytes to physical address space using the page table below. 0 8 1 6 2 3 3 11 4 7
For the subsequent problems, A through F, words are assumed to be 4 bytes, and the...
For the subsequent problems, A through F, words are assumed to be 4 bytes, and the references are word- addresses. Thus, the words in memory are located in word-addresses 0, 1, 2, As a comparison, note that byte-addresses for words are multiples of 4. Thus, the byte-addresses for words are 0, 4, 8, 12.. Problem B (2 pts). Assume a direct-mapped cache with two-word blocks and total size of 8 words. In the Bace balondiar(Noter Bleck 0 are the words...
Design a computer system with an 8-bit address bus, an 8-bit data bus and it uses...
Design a computer system with an 8-bit address bus, an 8-bit data bus and it uses isolated I/O. It has: 1128 bytes of PROM starting at address 00H (H meaning in hexadecimal) constructed usin ( one 64x8 chip and multiple 32x2 chips; g (2) 96 bytes of RAM constructed 32x4 chips; (3) an output device with a READY signal at address ABH; (4) an input device with a READY signal at address CDH; (5) a bidirectional input/output device with a...
3. Virtual Memory (20 points) An ISA supports an 8 bit, byte-addressable virtual address space. The...
3. Virtual Memory (20 points) An ISA supports an 8 bit, byte-addressable virtual address space. The corresponding physical memory has only 256 bytes. Each page contains 32 bytes. A simple, one-level translation scheme is used and the page table resides in physical memory. The initial contents of the frames of physical memory are shown below. VALUE address size 8 bit byte addressable each byte of addressing type memory has its own address 32 B page size physical memory size 256...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How many bits the virtual address contain? How many bits the physical address contain? bs Suppose now that some pages from the process have been brought into main memory as shown in the following figure: Virtual memory Physical memory Page table Frame #...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 091 86 30 3F 10 000 - 45 1 604FEO 23 38 1 00 BC OB 37 EB 0 OB 0 - 06 0 32 1 12 08 7B AD c 06 78 07 06 05 1 40 67 C2 3B 711 6E 0 911 AO B7 26 2DFO 0...
4. (20%) PC1 sends a 1,500 octet datagram (20-byte header and 1,480 bytes of data, IP ID = 677 to PC2 through the routers R1 and R2. The corresponding MTUs are given in the following diagram. Please show the information about IP packet identification, total packet length, IP flag bit Mand fragment offset in the IP header of each fragmented IP packet. R1 R2 MTU=1500 bytes MTU=1500 bytes PC1 MTU=500 bytes PC2 Fragment #1 Fragment #2 Fragment #2 Fragment ID...
Please show all work. I do not understand this question.
4. How many GRa are there in 9.3 Ci? Table 5. SI prefixes Factor Name Symbol Factor Name Symbol 1024 yotta Y 102 zetta Z 1018 exa E 1015 peta P 1012 tera T 109 giga G 106 mega M 103 kilo k 102 becte, h 101 deka da 10-1 deci d 10-2 centi c 10-3 milli m 10-6 micro u 10-9 vana n 10-12 pica p 10-15 femta f...
For the subsequent problems, A through F, words are assumed to be 4 bytes, and the references are word- addresses. Thus, the words in memory are located in word-addresses 0, 1, 2, As a comparison, note that byte-addresses for words are multiples of 4. Thus, the byte-addresses for words are 0, 4, 8, 12.. Problem B (2 pts). Assume a direct-mapped cache with two-word blocks and total size of 8 words. In the Bace balondiar(Noter Bleck 0 are the words...
Design a computer system with an 8-bit address bus, an 8-bit data bus and it uses isolated I/O. It has: 1128 bytes of PROM starting at address 00H (H meaning in hexadecimal) constructed usin ( one 64x8 chip and multiple 32x2 chips; g (2) 96 bytes of RAM constructed 32x4 chips; (3) an output device with a READY signal at address ABH; (4) an input device with a READY signal at address CDH; (5) a bidirectional input/output device with a...
3. Virtual Memory (20 points) An ISA supports an 8 bit, byte-addressable virtual address space. The corresponding physical memory has only 256 bytes. Each page contains 32 bytes. A simple, one-level translation scheme is used and the page table resides in physical memory. The initial contents of the frames of physical memory are shown below. VALUE address size 8 bit byte addressable each byte of addressing type memory has its own address 32 B page size physical memory size 256...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How many bits the virtual address contain? How many bits the physical address contain? bs Suppose now that some pages from the process have been brought into main memory as shown in the following figure: Virtual memory Physical memory Page table Frame #...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 091 86 30 3F 10 000 - 45 1 604FEO 23 38 1 00 BC OB 37 EB 0 OB 0 - 06 0 32 1 12 08 7B AD c 06 78 07 06 05 1 40 67 C2 3B 711 6E 0 911 AO B7 26 2DFO 0...
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