Question

4. (20%) PC1 sends a 1,500 octet datagram (20-byte header and 1,480 bytes of data, IP ID = 677 to PC2 through the routers R1 and R2. The corresponding MTUs are given in the following diagram. Please show the information about IP packet identification, total packet length, IP flag bit Mand fragment offset in the IP header of each fragmented IP packet. R1 R2 MTU=1500 bytes MTU=1500 bytes PC1 MTU=500 bytes PC2 Fragment #1 Fragment #2 Fragment #2 Fragment ID = Offset= M= Total Length — 5. (10%) PC1 sends a 1,500 octet datagram (20-byte header and 1,480 bytes of data, IP ID = 550 to PC2 through the routers R1 and R2. The corresponding MTUs are given in the following diagram. Please show the information about IP packet identification, total packet length, IP flag bit Mand fragment offset in the IP header of each fragmented IP packet. R1 MTU=1500 bytes R2 MTU=1500 bytes PC1 MTU-420 bytes PC2 Fragment #1 Fragment #2 Fragment #3 Fragment # 4 if you have Fragment ID = Offset = ME Total Length

Answer 1

Question 4)

Given data

Datagram size:1500B
Data size:1480B
Header size:20B
IP ID :677

	Fragment #1	Fragment #2	Fragment #3	Fragment #4
Fragment ID =	677	677	677	677
Offset =	0	60	120	180
M =	1	1	1	0
Total Length =	500	500	500	60

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Question 5)

Given data

Datagram size:1500B
Data size:1480B
Header size:20B
IP ID :550

	Fragment #1	Fragment #2	Fragment #3	Fragment #4
Fragment ID =	550	550	550	550
Offset =	0	50	100	150
M =	1	1	1	0
Total Length =	420	420	420	300