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Problem 7 For this differential amplifier, calculate the a) Differential gain, b) the Common Mode gain, and c) the Common Mod

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Here I am attaching two ways to solve this problem.25k E IV out I Vb IK { 2AK By super positian Theorem gain Terminet due to non inverting vt - Vb (24) - Vb (24) 24+ 25 Cut-u-arvout = 62 AV = 624 = At Vh - 25 . Gain due to Inverting Terminal 25k va in oft Vout {24k o-Vout 25k 뺥 Vout = -25 = À Va ForFor commonmode gain © Ac = A++* = 624-25= *s -0.04. Q Ć CMRR=1 CMRR = M = | 24.= 6245 124.981 - = 624.5 0.04 CMRR (dB) = 2025k NV Vout Va=V6x24 - V6 24 24+1 ke at node vy I = I2 Va -vy IK - Vy-vout 25k Va V6 24 1624 Yout - 25 25va- U624 25 - 1624-2Vout= - Vat 624 (N. a-V6L 25 - 25 Vout = ( 9 )va + (629) (va-vo) Ad AC

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