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The system below shows a simplified schematic of an oil transfer system between tanks, from left to right: L L The oil specif

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= 0.000063 Sed Q=85 gpm. 00063 m/s. D-a-sinch 0.0635m. Va 4.410.000003 10684 m/s 3.14 (0.0675) Po 0-77x100o=770kg/m3. M=27X10= 40787 (3) - NPSHAN = hsuct - P. Ixlooo lox no P9 NPSH is 240887 -0.959 ? 4.597 m > NPBHRcom. You Complaint d). Absolute Pre

using given data and relevant equations we can find the required variables

as per guideliens only first four parts are to be solve dfor rest parts post separatley qs again

for any doubts write in comments

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