Homework Answers
I will balance the first one by both methods, to give you an idea of how you'll do the other two. If you still have doubts, you can psot the question again and we will help you.
the reaction is I2O5 + CO ------> I2 + CO2
Let's write the half reactions and balance it basic medium:
5H2O + I2O5 + 10e-
---------> I2 + 10OH-
(2OH- + CO --------> CO2 + 2e-
+ H2O)*5
5H2O + I2O5 + 10e-
---------> I2 + 10OH-
10OH- + 5CO --------> 5CO2 +
10e- + 5H2O
I2O5 + 5CO ---------> I2 + 5CO2
In acid medium:
10H+ + I2O5 + 10e-
---------> I2 + H2O
(H2O + CO --------> CO2 + 2e- +
2H+)*5
10H+ + I2O5 + 10e-
---------> I2 + H2O
5H2O + 5CO --------> 5CO2 +
10e- + 10H+
I2O5 + 5CO ---------> I2 + 5CO2
The other two reactions are balance in similar way.
Hope this helps
Add Answer to:
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