Question

can you show me step by step how to get solve this? thank you

Question 1 Solve the following circuit using superposition Is S R₂ R₃ < 1.2 k2 18 12 600 MA

Answer 1

Summary- This problem is solved by using the basics of Network Analysis using the superposition theorem. Below are the details of solution uploaded in sequence.

10 & w NW To ww polalled = 5x3 573 Step G Reduce Sources the circuit as possible without disturbing the and then Apply super position Theorem. Now, circuit will be, 4 Viss 10 -ММ — ola 10 Vsi Fig. O ① ckt Step ④ Due Apply super position Theorem to Fig only source of Vsi = 10v While usa = short ckt Is = open ckt (voltage source) (current source.

Now, circuit will be. 3 V 4 ww Fig ③ :- ckt De to source (Vs, =lo v alone) node Apply Nodal Analysis at V By KCL Va + Va t x + 10 =0 Vx + y (8) + bet to ao 4 47 1418x + 96 Vx + 1 564 lulux t 96 x + 188 x = -1880 425 Vx = -1880 Vy = -376 -1880 425 85

Now, using Voltage Division Rue, E-376 * 42 (RAR) = -1-376 * 4 = 85 . (4+1) (s. Due to opposite terminal) Voltage Division Rule is Applicable only like Enample Note :- Voltage series for Division m 80 NOW, V = + 376 * *8*4 47 85 256

Step ③ - NOW Due to let Now, circuit will be current source alone v" be voltage Pource Tranformation Technique. VU + Fig. © CKE Due to current source alone Circuit 78 Reduced as follows, VH + ♡ Html = ( 0.2 x 15 ) 80, Again Applying Voltage- Division Rule.

Step 4 - Now, Voltage source (V3 =10) alone... Circuit will be 3x4 (3 . W 7 Nu + w alin Fig. ckt Due to Vss alone Reduced Okt as followers 10 - vit + Now, Again using voltage Division Rule = Yo 856 4+ 425 V = 10 * 4 4+ 15 + 12 Bol" - Yu8 , 15 8 +12 7 ③ 85

By super position theorem, Vo = V + Vor at von (Due to (Due to (Due to Vsi alone) Is alone) Viss alone) from, egnis 6 § 256 85 + 448 84 425 & Hence, Hence, = 3436 (01) =8.08 V 425