A 2.0m length of metal wire is connected to a 1.5 V battery, and a current of 5.0mA flows through it. What is the diameter of the wire? (The resistivity of metal is 2.24
R = V/I = 1.5/ 0.005 = 300 ohm
R = resisitivity *( L/ (pi *r2))
r=6.89 micro meter
diameter = 2r =1.38 *10^-5 m
Resistance = resistiviy x length / area
resistance by equation = 1.5 / 5 x 10-3 = 3 x 102 ohm
3 x 102 = 2.24 x 108 x 2 / pi x r2
Solving we get r = 6.89 x 103 m
ANS diameter = 1.38 x 104 m
R = V/I
R = (1.5V)/(5mA) = 300 Ohms
A = pL/R = (2.24*108)(2)/300 = 1.6128
Area of a circle = d2(pi)/4
d = sqrt(4*1.6128/pi) = 1.433m
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