Critical Values for the Correlation Coefficient | ||
n | alpha = .05 | alpha = .01 |
4 | 0.95 | 0.99 |
5 | 0.878 | 0.959 |
6 | 0.811 | 0.917 |
7 | 0.754 | 0.875 |
8 | 0.707 | 0.834 |
9 | 0.666 | 0.798 |
10 | 0.632 | 0.765 |
11 | 0.602 | 0.735 |
12 | 0.576 | 0.708 |
13 | 0.553 | 0.684 |
14 | 0.532 | 0.661 |
15 | 0.514 | 0.641 |
16 | 0.497 | 0.623 |
17 | 0.482 | 0.606 |
18 | 0.468 | 0.59 |
19 | 0.456 | 0.575 |
20 | 0.444 | 0.561 |
25 | 0.396 | 0.505 |
30 | 0.361 | 0.463 |
35 | 0.335 | 0.43 |
40 | 0.312 | 0.402 |
45 | 0.294 | 0.378 |
50 | 0.279 | 0.361 |
60 | 0.254 | 0.33 |
70 | 0.236 | 0.305 |
80 | 0.22 | 0.286 |
90 | 0.207 | 0.269 |
100 | 0.196 | 0.256 |
Solution:-
Null Hypothesis H0: The population correlation coefficient is not significantly different from 0.( \rho = 0)
Alternate Hypothesis HA: The population correlation coefficient is significantly different from 0.( \rho 0)
Significance level = 0.05
Degree of freedoms:-
D.F = n - 2
D.F = 60
Test statistics:-
t = 0.968
There are two critical values + 0.254
rCritical = + 0.254
tCritical = + 2.034
p value for test = 0.337
Since p value(0.337) is greater than the significance value so we have to accept the null hypothesis.
Because the value of the test statistics is lies below the positive critical value there is not sufficient evidence to support the claim that there is linear correlation between two variables.
Critical Values for the Correlation Coefficient n alpha = .05 alpha = .01 4 0.95 0.99...
Critical Values for the Correlation Coefficient n alpha = .05 alpha = .01 4 0.95 0.99 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.59 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.43 40 0.312 0.402 45 0.294 0.378...
please answer all parts 1 Critical Values of the Pearson Correlation Coefficient Critical Values of the Pearson Correlation coefficient a = 0.05 a = 0.01 0.950 10.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 10.798 0.632 0.765 0.602 0.735 0.576 0.708 0.553 0.684 0.532 0.661 0.514 0.641 0.497 0.623 0.482 0.606 0.468 10.590 0.456 0.575 0.444 0.561 0.396 0.505 10.361 10.463 sand Print Done 17 18 19 0.402 0.468 0.590 0.456 10.575 0.444 0.561 0.396 0.505 0.361 0.463...
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Critical Values of the Pearson Correlation Coefficient r n α=0.05 α=0.01 NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468...
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n α=0.05 α=0.01 NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25...
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