PC: Point of Curve
PT: Point of tangent
from the given plan,
the stationing of PC is at 3+21.19 = 321.19 ft
the stationing of PT is at 7+13.16 = 713.16 ft
the radius of the curve, R = 275.00 ft
intersection angle, delta
length of curve, L = 713.16-321.19 = 391.97 ft
L = R*(delta)
delta = 397.97/275 = 1.4253 radians = 81o39'58.6"
external distance, distance other than in curve = (321.19-200)+(800-713.16) =208.03
Kindly see the answers and let us know if you need more details. Only the first question is to be solved as per the policy norms.
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