Question

TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.1. A sample of 90 households is drawn. Use the Cumulative Normal Distribution Table if needed. Part 1 of 5 What is the probability that the sample mean number of TV sets is greater than 27 Round your answer to four decimal places. The probability that the sample mean number of TV sets is greater than 2 is Part 2 of 5 What is the probability that the sample mean number of TV sets is between 2.5 and 37 Round your answer to four decimal places The probability that the sample mean number of TV sets is between 2.5 and 3 is . Part 3 of 5 Find the 10 percentile of the sample mean. Round your answer to two decimal places. The 10 percentile of the sample mean is

Answer 1

X~ Nl2.241.1) 1a PL x > 2) = I-Plz C 2 2.30 =0.9807 -1). Pl.2.5CXC 3) = PL 2C37.29.)-PL2-2.5-.947 odlu go - PC2<0.76 XJ 90) - Plac Xu9o) - P2C 0,UMJg. 1.1 Ic) PLECYD = 0.1o 70.0125 p(242.94 ) = o.do It is go 20.l. = 22.94 1.29 Tot (056 = 12.09 la) PL X L2= PL22 22.24 10.0192 10 PLXC2) PLZ C 22.34 ) = P(Z2-0.24) 1.1 TI 10.4136