What types of design loads in load combination equations are based on geographic information?
What types of design loads in load combination equations are based on geographic information?
Homework Answers
Few types of loads that are applied on structure during design will depend on the geographical location.
They are:
Wind load: as wind speed varies at coastal, hilly, plain areas.
Earthquake load: Depends on the probability of earthquake frequency and intensity occuring in a region. Country is divided in to seismic zones.
Snow load: It is a type of roof load. Snow varies from place to place. It varies from absolute zero to very high intensities. So we refer to the snow load maps.
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What types of design loads in load combination equations are
based on geographic information?
Following loads act on a roof. What is the design roof load as per LRFD design...
Following loads act on a roof. What is the design roof load as per LRFD design method? Dead load (D) = 200 psf Roof live load (L.) = 40 psf Rain load(R) = 20 psf Snow load (S) = 45 psf Wind load (W) = -32 psf (uplift) 312.5 psf 334.4 psf 256.7 psf 211.3 psf
Please show the steps The loads on columns of the MWFRS from different load types are...
Please show the steps
The loads on columns of the MWFRS from different load types are shown in Figure 3. Bracing members in compression will yield and can be ignored. It is required to a) Determine the ultimate axial design compression load (Pu) for the columns D9 and D13. b) Use the column design tables to find the lightest weight section, W10, W12, or W14, that will work for the critical column. c) Once you have selected a section, verify...
2. Calculate the factored design load (ASD) for 10 ft by 12 ft tributary area of...
2. Calculate the factored design load (ASD) for 10 ft by 12 ft tributary area of a wall (lateral load) based on the following estimated loads: [10 points) Wind 28 lb/ft2 Live 5000 lb Governing ASD factored load combination equation Governing factored design load (k)
Based on tributary load analysis, the dead and live loads, wd and wų, respectively, acting on...
Based on tributary load analysis, the dead and live loads, wd and wų, respectively, acting on a beam in a vertical load resisting system are shown below. The concrete is normalweight with compressive strength f=5000 psi. Note that the given dead load includes the self-weight of the beam and slab. Section wp=1.2 kip/ft, wu=1.5 kip/ft be-45 inch 5 inch 1 30 inch B A 10 inch In=10 ft 1. Design and detail the beam for positive flexure at section A....
All given loads are service loads. A column in a building is subjected to the following...
All given loads are service loads. A column in a building is subjected to the following load effects: 9 kips compression from dead load 5 kips compression from roof live load 6 kips compression from snow 7 kips compression from 3 inches of rain accumulated on the roof 8 kips compression from wind a. If load and resistance factor design is used, determine the factored load Note 2-1 (required strength) to be used in the design of the column. Which...
5) Load Combination and Mohr Circle: The beveled 2 gear is subjected to the loads shown....
5) Load Combination and Mohr Circle: The beveled 2 gear is subjected to the loads shown. Determine the maximum normal (principal) stresses and maximum shear stress at point A. The shaft has a diameter of 1 inch and is fixed to the wall at C (20 points) 200 lb 8 in. in. 75 lb 125 lb
Find the design shear load for the following simply supported beam if the dead loads (include...
Find the design shear load for the following simply supported beam if the dead loads (include beam weights) is 1 k/ft and live load 2 k/ft., span length 35 ft. your answer should be in kips. span
For the load depicted below, to use super position how would the loads be divided? What boundary ...
For the load depicted below, to use super position how would the loads be divided? What boundary conditions would be used? How would the equations for each section be grouped? 2) 30 kips 18 kips/ft 12 8'--> 1 16 kips
For the load depicted below, to use super position how would the loads be divided? What boundary conditions would be used? How would the equations for each section be grouped? 2) 30 kips 18 kips/ft 12 8'--> 1 16 kips
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load...
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy= 40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load...
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy=40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
Following loads act on a roof. What is the design roof load as per LRFD design method? Dead load (D) = 200 psf Roof live load (L.) = 40 psf Rain load(R) = 20 psf Snow load (S) = 45 psf Wind load (W) = -32 psf (uplift) 312.5 psf 334.4 psf 256.7 psf 211.3 psf
Please show the steps
The loads on columns of the MWFRS from different load types are shown in Figure 3. Bracing members in compression will yield and can be ignored. It is required to a) Determine the ultimate axial design compression load (Pu) for the columns D9 and D13. b) Use the column design tables to find the lightest weight section, W10, W12, or W14, that will work for the critical column. c) Once you have selected a section, verify...
2. Calculate the factored design load (ASD) for 10 ft by 12 ft tributary area of a wall (lateral load) based on the following estimated loads: [10 points) Wind 28 lb/ft2 Live 5000 lb Governing ASD factored load combination equation Governing factored design load (k)
Based on tributary load analysis, the dead and live loads, wd and wų, respectively, acting on a beam in a vertical load resisting system are shown below. The concrete is normalweight with compressive strength f=5000 psi. Note that the given dead load includes the self-weight of the beam and slab. Section wp=1.2 kip/ft, wu=1.5 kip/ft be-45 inch 5 inch 1 30 inch B A 10 inch In=10 ft 1. Design and detail the beam for positive flexure at section A....
All given loads are service loads. A column in a building is subjected to the following load effects: 9 kips compression from dead load 5 kips compression from roof live load 6 kips compression from snow 7 kips compression from 3 inches of rain accumulated on the roof 8 kips compression from wind a. If load and resistance factor design is used, determine the factored load Note 2-1 (required strength) to be used in the design of the column. Which...
5) Load Combination and Mohr Circle: The beveled 2 gear is subjected to the loads shown. Determine the maximum normal (principal) stresses and maximum shear stress at point A. The shaft has a diameter of 1 inch and is fixed to the wall at C (20 points) 200 lb 8 in. in. 75 lb 125 lb
Find the design shear load for the following simply supported beam if the dead loads (include beam weights) is 1 k/ft and live load 2 k/ft., span length 35 ft. your answer should be in kips. span
For the load depicted below, to use super position how would the loads be divided? What boundary conditions would be used? How would the equations for each section be grouped? 2) 30 kips 18 kips/ft 12 8'--> 1 16 kips
For the load depicted below, to use super position how would the loads be divided? What boundary conditions would be used? How would the equations for each section be grouped? 2) 30 kips 18 kips/ft 12 8'--> 1 16 kips
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy=40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
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