Question

01 2 3 4 Delermine (a) the y2 lest atalistic () Uhe dearees of freedom, fe) the P-value, and (d) test e hyoothesis at the -005 Jeve srifcarce Expected 6 25.3 162 14s 40S e random vanable X is bnemial wth n 4, p Ho. cick the lan to vlew e ch-scuero dstdbuticn aNo IRound to two decimal places as needed Thera andagraas of freedom. The Pvalua is What is the conclusion of the test at the 0.05 level of signficance? then thanul hypotheais, because the P-value Thane Aidenca that the random vadable X is not bincmial with n-4, 0 -0.8

Answer 1

Following table shows the calculations:

	O	E	(O-E)^2/E
	3	1.6	1.225
	39	25.3	7.41857708
	120	152.1	6.77455621
	442	405.5	3.28545006
	386	405.5	0.9377312
Total	990	990	19.6413145

(a)

The test statistics is

19.64

(b)

The degree of freedom:

df=n-1=4

(c)

The p-value is 0.0006

(d)

Since p-value is less than 0.05 so we reject the null hypothesis.

There is evidence that random variable X is not binomial with n=4 and p=0.80