Question

A very long, straight solenoid with a cross-sectional area of 1.92 cm2cm2 is wound with 86.9 turns of wire per centimeter. Starting at tt = 0, the current in the solenoid is increasing according to i(t)=i(t)= (( 0.164 A/s2A/s2 )t2)t2. A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid.

Part A

What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is 3.2 AA ?

Answer 1

Hare: 19.2.cm? = 1.92.xlv.m? It has_86-9. turns-pez Ceantimeten - Se b r No. of_turns :_2609_mail_8690 m - length oool __tums_at_Centre (N) = 5 - current increases = 0.162t² The average induced emf in this winding is given by faraday's law :- og tfart Cart N Tdt) ♡ = Magnetic flux.. $ = BA - denilt). A _N{Moni[£):) = 4yN_06_d1441 {B=anit H 6 dt dt.

ta thonn A d (0-1694?) TE= 0.164 flan nabatt Now i = 3.2A = 0.164+? to her han = 4042 sec E = 0.164 640x16?)( 8690)(5) 61-92x104) 2x4:42] TE = 0 : 52x10-5 v