In mice, the gene for tail length has 2 alleles: short is dominant to long. However,...
In mice, the gene for tail length has 2 alleles: short is dominant to long. However, short tail is lethal in the homozygous condition. A short tail mouse is crossed to a long tail mouse. What are the expected phenotype's and their ratios of the mouse pups in this litter?
options:
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25% long tails |
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75% long tails |
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100% long tails |
|
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No long tails |
|
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50% long tails |
|
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33% long tails |
|
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67% long tails |
Following up to the previous question, 2 short tail mice are crossed together. What are the expected phenotypes and their ratios of the mouse pups from this litter?
options:
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No long tails |
|
|
33% long tails |
|
|
50% long tails |
|
|
75% long tails |
|
|
25% long tails |
|
|
67% long tails |
|
|
100% long tails |
A mouse typically has a litter of 8 pups with each pregnancy. How many live born pups would you expect to find in a litter from the cross in the previous question?
options:
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8 pups |
|
|
2 pups |
|
|
4 pups |
|
|
6 pups |
|
|
No pups are live born |
Homework Answers
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In mice, the gene for tail length has 2 alleles: short is
dominant to long. However,...
Tail length is a genetic trait in mice. A purebred short-tail mouse is crossed with a...
Tail length is a genetic trait in mice. A purebred short-tail mouse is crossed with a hybrid short-tail mouse. What is the chance of having F1 long-tail mouse?
In mice, short tails (l) are recessive to long tails (L), and tan coat color (b)...
In mice, short tails (l) are recessive to long tails (L), and tan coat color (b) is recessive to black (B). An LLbb mouse is bred to an llBB mouse. a.What are the expected phenotypic ratios in the F1 generation? b.If two of the F1 progeny are bred, what are the predicted phenotypic ratios in the F2 progeny?
Assume that tail length in mice is a quantitative trait involving two genes, each with 2...
Assume that tail length in mice is a quantitative trait involving two genes, each with 2 alleles. One allele at each gene contributes to long tails, the other allele at each gene does not (small tails). The genes are located on different autosomes. Mice with 0 contributing alleles have tails that are 4 cm in length; mice with tails with 4 contributing alleles are 12 cm in length. Determine the phenotypic ratio from an F2 from a true breeding parent...
2. In certain cats, tail length-long, short, manx (no tail) - is determined by a gene...
2. In certain cats, tail length-long, short, manx (no tail) - is determined by a gene that demonstrates incomplete dominance. a. Make up letters to represent the long & manx alleles. b. Give the genotypes for each tail type. Long-tailed Short-tailed Manx c. Construct a Punnett square to illustrate a cross between a short-tailed cat and a man. What is the probability that the resulting kittens will be manx? Activity 3: Codominance 1. In codominance, the symbols for alleles are...
Questions 1-6 BIOL 366 Mono and Dihybrid Crosses Recitation Problem Set Directions: For problems 1-6, do...
Questions 1-6
BIOL 366 Mono and Dihybrid Crosses Recitation Problem Set Directions: For problems 1-6, do the following A. List how many genes are involved B. List how many alleles are involved. C. Identify symbols and genotypes / phenotypes D. List the genotypes of the parents E. Diagram and complete a Punnett square F. Give the phenotype percentages/ration of the offspring 1. In dogs, erect ears (E) is dominate over droopy ears (e). What are the results if two heterozygous...
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Which of the following is not one of the ways that meiosis can introduce variability into a population via sexual reproduction? meiosis never introduces genetic variation production of diploid gametes independent assortment along the metaphase plate crossing over random fertilization The role of meiosis in Mendel's law of segregation is that it allows crossing over to occur. it allows genes to be duplicated. it separates sister chromatids and exact copies of genes it separates homologous chromosomes and therefore gene alleles...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...
for questions 25 - 26 using the letters below. This set of questions refers to Mendel’s...
for
questions 25 - 26 using the letters below. This set of questions
refers to Mendel’s plants with either Purple flowers or White
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none of these answers 25. A purple flowering pea plant of unknown
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determine the genotype of a purple flowering plant of unknown
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Merritt, 2016 BIO 1511 NAME:F. I.) 10-15 Post Lab #10 Post-LabE19: BASIC GENETICS PROBLEMS # Correct...
Merritt, 2016 BIO 1511 NAME:F. I.) 10-15 Post Lab #10 Post-LabE19: BASIC GENETICS PROBLEMS # Correct Answers: (16) (Last) Lab Day: MWF(circle one) Solve the genetics problems in this handout. For all problems, assume complete dominance, assume one gene codes for one trait, and assume there are only 2 different alleles possible for each gene (dominant or recessive) 1. If a homozygous dominant red flowered plants are crossed with homozy phenotypes and genotypes of the offspring? Show the genotypes of...
need help with question 2, 4, 6 a.&b. 2. For a (fictitious) haploid fungus, the starting...
need help with question 2, 4, 6 a.&b.
2. For a (fictitious) haploid fungus, the starting point in the biosynthesis of the amino acid arginine is Compound X, which is always present in, and absorbed from the environment. The arginine biosynthetic pathway is: Enzyme B → Compound Y Compound z Enzyme C Compound X Enzyme A arginine A mutant strain of genotype a (lacking enzyme A) is crossed to a mutant strain of genotype c (lacking enzyme C). What proportion...
2. In certain cats, tail length-long, short, manx (no tail) - is determined by a gene that demonstrates incomplete dominance. a. Make up letters to represent the long & manx alleles. b. Give the genotypes for each tail type. Long-tailed Short-tailed Manx c. Construct a Punnett square to illustrate a cross between a short-tailed cat and a man. What is the probability that the resulting kittens will be manx? Activity 3: Codominance 1. In codominance, the symbols for alleles are...
Questions 1-6
BIOL 366 Mono and Dihybrid Crosses Recitation Problem Set Directions: For problems 1-6, do the following A. List how many genes are involved B. List how many alleles are involved. C. Identify symbols and genotypes / phenotypes D. List the genotypes of the parents E. Diagram and complete a Punnett square F. Give the phenotype percentages/ration of the offspring 1. In dogs, erect ears (E) is dominate over droopy ears (e). What are the results if two heterozygous...
Which of the following is not one of the ways that meiosis can introduce variability into a population via sexual reproduction? meiosis never introduces genetic variation production of diploid gametes independent assortment along the metaphase plate crossing over random fertilization The role of meiosis in Mendel's law of segregation is that it allows crossing over to occur. it allows genes to be duplicated. it separates sister chromatids and exact copies of genes it separates homologous chromosomes and therefore gene alleles...
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for
questions 25 - 26 using the letters below. This set of questions
refers to Mendel’s plants with either Purple flowers or White
flowers A. PP B. Pp C. pp D. PP or Pp E. Pp or pp F. PP or pp G.
none of these answers 25. A purple flowering pea plant of unknown
genotype would be best described by which answer above 26. To
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Merritt, 2016 BIO 1511 NAME:F. I.) 10-15 Post Lab #10 Post-LabE19: BASIC GENETICS PROBLEMS # Correct Answers: (16) (Last) Lab Day: MWF(circle one) Solve the genetics problems in this handout. For all problems, assume complete dominance, assume one gene codes for one trait, and assume there are only 2 different alleles possible for each gene (dominant or recessive) 1. If a homozygous dominant red flowered plants are crossed with homozy phenotypes and genotypes of the offspring? Show the genotypes of...
need help with question 2, 4, 6 a.&b.
2. For a (fictitious) haploid fungus, the starting point in the biosynthesis of the amino acid arginine is Compound X, which is always present in, and absorbed from the environment. The arginine biosynthetic pathway is: Enzyme B → Compound Y Compound z Enzyme C Compound X Enzyme A arginine A mutant strain of genotype a (lacking enzyme A) is crossed to a mutant strain of genotype c (lacking enzyme C). What proportion...
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