8Mg + S8 → 8MgS
If 80 moles of Mg and 15 moles of S8 are allowed to react, _?_moles of MgS will be formed. Mg is the _?_ (limiting or excess) reactant and S8 is the _?_(limiting or excess) reactant. _?_moles of the excess reactant will remain unreacted.
8Mg + S8 → 8MgS
According to the above balanced equiation ,
8 moles of Mg reacts with 1 mole of S8
8x10=80 moles of Mg reacts with 1x10 = 10 mole of S8
So 15 - 10 = 5 moles of S8 left unreacted in the solution.So S8 is the excess reactant.
Since all the mass of Mg completly reacted, Mg is the limiting reactant.
From the balanced equation ,
8 moles of Mg produces 8 moles of MgS
So 80 moles of Mg produces 80 moles of MgS
Therefore the number of moles of MgS produced are 80 moles
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