Homework Answers
The 2 functions function1 and function2 are defined inside main. So, the values of x relies on the main function. The function3 is defined inside function1 and function2.
The dependency of values in static scoping is related as follows :
The first value of x will be printed in function1 which will be returned by function3.
function1 depends on main( ) and the value of x will be passed from main( ) to function1 as y and the value is 10.
function1 will compute the new value of x as x = y + 5 = 10 + 5 = 15 and this will be returned by function3.
The second value of x will be printed in function2 which will be returned by function3.
function2 depends on main( ) and the value of x will be passed from main( ) to function2 as y and the value is 10.
function2 will compute the new value of x as x = y + 10 = 10 + 10 = 20 and this will be returned by function3.
So, the final output using static scoping is :
15
20
The dynamic scoping chain is :
main( ) -----> function1( ) ---------> function3( ) ---------> function2( ) ----------> function3( )
The dependency of values in dynamic scoping is related as follows :
The first value of x is printed inside function1.
function1 depends on main( ) and the value of x will be passed from main( ) to function1 as y and the value is 10.
function1 will compute the new value of x as x = y + 5 = 10 + 5 = 15 and this will be returned by function3.
The second value of x is printed inside function2.
function2 will operate after function1 has completed execution and the value of x is dynamically changes to 15 by function1 and function2 is dependent on function1 and function3.
The value of x passed to function2 as y is 15 and not 10.
In function2, the new value of x is calculated as x = y + 10 = 15 + 10 = 25 and this is returned by function3.
So, the final output using dynamic scoping is :
15
25
| static scope output | dynamic scope output |
| 15 | 15 |
| 20 | 25 |
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