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QUESTION 4 The temperature distribution for a long fin with uniform cross section is cosh[m(L - x)] cosh(ml) where b means ba

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Sowtion: d = 1.5cm = 0.015 m Ka 380 wlink pa 27= Td = 3.14% 0.015 = 0.0471 m. Ai gde = 3.14 x 0.015 x Q.2 = 0.0094 m2. m= 6mt

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