Question

Can you please help me with question 2a-c in step-by-step explanation. I did poorly on this question.

2. (10 points) A 6 cm3 ce cube is floating in a glass of water. The glass has a cross-sectional area of 50 cm and it is filled with water to a height of 12 cm. Ice has a density of pice 917 kg/m a. Calculate the magnitude of the buoyant force on the ice cube n'y loon m b. Find the percentage of the ice cube sticking out above the surface of the water 0.75 E look. at A um V 6.0 x IO 6.0 x o C2 la 0012 hely a small pertenby ice uauwd A 31 out of a dass of water be shaking S. 33 33.

Answer 1

a)

the buoyant force is supporting the weight of the cube since cube is floating

hence F_b = buoyant force = weight of cube = mg = ( $\rho$ _ice V_ice)g = (917) (6 x 10^-6) (9.8) = 0.054 N

c)

Water will remain same .

The ice cube displaced same amount of water as its weight. so when the ice melts , it simply displaces the same volume. hence the water level remains same