Question

You have been asked to evaluate the economic implications of various methods for cooling condenser effluents from a​ 200-MW steamelectric plant. There are two basic types of cooling​ towers: wet and dry.​ Furthermore, heat may be removed from condenser water by​ (1) forcing​ (mechanically) air through the tower or​ (2) allowing heat transfer to occur by making use of natural draft.​ Consequently, there are four basic cooling tower designs that could be considered. Assuming that the cost of capital to the utility company is 10​%

per​ year, your job is to recommend the best alternative​ (i.e., the least expensive during the service​ life). Further, assume that each alternative is capable of satisfactorily removing waste heat from the condensers of a​ 200-MW power plant. What noneconomic factors can you identify that might also play a role in the​ decision-making process?

LOADING...

Click the icon to view the alternatives description.

LOADING...

Click the icon to view the interest and annuity table for discrete compounding when

iequals=1010​%

per year.

The AW of Wet​ Tower, Mechanical Draft is

​$negative 2,205,478−2,205,478.

​(Round to the nearest​ dollar.)The AW of Wet​ Tower, Natural Draft is

​$nothing.

​(Round to the nearest​ dollar.)



Ompuunuiry well - 10% The AW of Wet Tower, Mechanical Draft is $ - 2,205,478. (Round to the nearest dollar.) The AW of Wet To
our lob is to recommend the best alternative ie, the least expensive during the service life). Further, assume that each alte
0.6830 Discrete Compounding; 1= 10% Single Payment Uniform Series Compound Compound Sinking Amount Present Amount Present Fun
1.9487 2.1436 2.3579 2.5937 2.8531 3.1384 3.4523 3.7975 4.1772 4.5950 5.0545 5.5599 6.1159 6.7275 7.4002 8.1403 8.9543 9.6497
0 0
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Answer #1

AW of wet tower mech draft = -3000000*(A/P,10%,30) - 40*2*74.6 * 24*365 *0.022 / 0.9 - 20*1.5*74.6*24*365*0.022 / 0.9 - 130000

= -3000000*0.1061 - 40*2*74.6 * 24*365 *0.022 / 0.9 - 20*1.5*74.6*24*365*0.022 / 0.9 - 130000

= -2205478.13 ~ -2205478

AW of wet tower natural draft = -8900000*(A/P,10%,30) - 20*1.5*74.6*24*365*0.022 / 0.9 - 100000

= -8900000*0.1061 - 20*1.5*74.6*24*365*0.022 / 0.9 - 100000

= -1523520.40 ~ -1523520

AW of dry tower mech draft = -5000000*(A/P,10%,30) - 20*2*74.6 * 24*365 *0.022 / 0.9 - 40*1.0*74.6*24*365*0.022 / 0.9 - 130000

= -5000000*0.1061 - 20*2*74.6 * 24*365 *0.022 / 0.9 - 40*1.0*74.6*24*365*0.022 / 0.9 - 130000

= -1938447.73 ~ -1938448

AW of dry tower natural draft = -9100000*(A/P,10%,30) - 40*1.0*74.6*24*365*0.022 / 0.9 - 100000

= -9100000*0.1061 - 40*1.0*74.6*24*365*0.022 / 0.9 - 100000

= -1704483.87 ~ -1704484

Annual cost of wet tower natural draft is lowest, it should be selected

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