ntermediate. Do not explicity draw hydrogen atoms on the intermediate. OH CH,
Draw the products of the reactions. Include hydrogen atoms. Select Draw Rings More Erase HC=CH .CH + OH → Hac— ——o— CH3 HC–CH CEO II - + / Q 2 a
Draw the products of the recations. Include hydrogen atoms Score: 77.8% Resources Grove Up O Hint 18 > Draw the products of the reactions. Include hydrogen atoms. Select Draw Rings More Erase HỌC & CH, | HC=CH C-0-c CH + H2O HC-CH Select Draw Rings More COM 2 @ HC-CH CH-OH HỊC-C- CH HC-CH Hello @ 2
draw the products of the reaction. include hydrogen atoms. Draw the products of the reactions. Include hydrogen atoms. Select Draw Rings More Erase HC=CH H+ La || H H.C—&— —0-6 CH + HO H* CH + H20 = ll CH3 HC—CH el 3 Q121@ We were unable to transcribe this image
Complete the ionization reaction of butanoic acid (CH,CH,CH,COOH) in water. Include all hydrogen atoms and charges. Select Draw Rings More Erase // ICOH +H,0- HyC-CH2-CH2-C-OH + 0 2
Draw the products of the reactions. Include hydrogen atoms. Select Draw Rings More Erase // ICOH H₂C 10-5 HC=CH. -0-C CH + H20 - HOẠCH Erase Select Draw Rings More Select Erase Draw Rings More HC=CH CH + OH HO-CH HC-0-0-0- | CH - @ 2
Draw the products of the reactions. Include hydrogen atoms. Select Rings Draw More Co н HC—СH H CH +HO Нас—С HC-CH CH Complete the given reactions. Add hydrogen atoms and charges to the appropriate atoms. Reaction A Select Draw Rings Erase More N Na H CH +NaOH heat H Draw all of the expected products from the reaction: Draw the appropriane number of hydrogens on oxygen and nitrogen ings Select Draw More trase CH ON (2 equiv.) NH
a) Draw the complete structure of propane. (Draw all hydrogen atoms.)b) Draw the structure of propane in skeleton mode or as a bond-line structure. (Do not draw the hydrogen atoms.)
Draw the organic product formed in the reaction. Include all hydrogen atoms. Select Draw Rings More 1 mol HC OH CH + = HO-POH -0
Draw step one of the mechanism (first elimination). Do not explicitly draw any hydrogen atoms in the product of this reaction. Include lone pairs in your answer. In this step eliminate the Cl on the secondary carbon NOT the Chlorine on the primary carbon. CH 3 H3C NH Edit H3C CI Cl
Draw stearic acid (octadecanoic acid). You do not need to draw hydrogen atoms attached to carbon atoms. Draw stearic acid (octadecanoic acid). You do not need to draw hydrogen atoms attached to carbon atoms.