Question

Instructions: Please read each problem and the information carefully. Circle the correct answer choice or fill in the blanks as asked for in the problem. If no correct answer is shown give your answer in (D) Numbers in the symbols represent the number of points for that problem (6) 1. A 26.5 F capacitor and a 75.8 capacitor are connected in parallel across a 12.0V potential difference. Determine the total energy stored in the capacitors Answer: (a) 5.22 m). (b) 6.52 m. 7.37 m). (d) 8.09 m). (6) 9.53 ml. ( [6] 12. For the circuit shown, R. - 65.80, R. - 46.5A, R, -78.6 and Re-25.60. Determine the equivalent resistance between aand b. 18.01 Rb Answer: (a) 13.30 1760. (c)20.2 0. (d) 23.00. (c) 26.3 (0 SEWW147.50 5.00 [10] #3. Circle the letters corresponding to the TRUE statements Statements: (a) Capacitors connected in series have the same electrical charge. Resistors connected in series have th e potential difference across cach. Dok The resistivity of a material is temperature dependent. In an R-C circuit, the capacitor is considered to be fully charged (RxC) seconds after the switch is closed. (e) For a nonmetal the resistivity increase the temperature increases Cat C 453up) Use the figure at the right for problems 4 - 6. +(62UF) For the circuit consisting of air filled, parallel plate - 17.5 UF capacitors, G. - 15.3 E, C = 25.6 F, C- 36.4 F, G-62.2 F Cztlig (36tut and C3-85. 4F, connected as shown at the right. +35.4UF) [6] 84. Determine the equivalent capacitance between points A and B. Answer: @) 16.6 . (b) 19.4 F. (c) 22.0 pF. (d) 24.4 F. (e) 26.8 F. ( _ =121.8 VF 1515. A potential difference of 15.0 volts is now applied across points A and B. What charge will be on ! Answer: (a) 249 (6) 396 C. (c) 440 u. (d) 520 uc. (c) 640 C. (1 [5] #6. A material of dielectric constant 5.6 is placed so as to completely fill between the plates of capacitor C. The new value of the capacitance of Csis Answer: (a) 221 F. (b) 347 F. ©) 478 F. (d) 593 uF. () 630 uF. (1) [8] 7. Circle the TRUE statements below. Statements: (a)) Magnetic fields can be caused by electric currents and magnets. b) A charged particle moving in a magnetic field will experience a force that is perpendicular to the velocity of the particle. TC) The force on a charged particle due to a magnetic field will cause the particle to speed up until it explodes. To Like magnetic poles attract. [6] 88. A 350.0 m long section of a certain wire (resistivity = 1.63 x 10 c m ) at room temperature has a circular Cross section of radius 15.2 x 10m. Determine the value of its resistance at room temperature Answer: (a) 6.15 m2. (b) 7.86 m2. (e) 10.2 m2. (d) 11.5 m2. (e) 13.0 m2.01.1910 70.2 [8] 9. Circle the FALSE statement(s) below Statements: (a) A superconductor is a material that loses its electrical resistance below a certain temperature. If a piece of silicon is "doped" with the appropriate element it becomes useless and is referred to as "dopey material. (c) If a small amount of certain elements is added to an insulating material the electrical properties of insulating material may be changed significantly (d) A DMM is used to measure voltage, current and resistance.

Answer 1

G= 26.5 MF = 26.5X10 of C22 75.8 XP a 75.8 * 10 of 12 V legzetle= (26.5+ 7518) x206 z. 1023 X 106 Here, v= 12 volt; Total energy stormed in the eineent will be Watceava

N = 2Cegar > X 1023x0X10? » N= 7.365 68 16 37 wr 7.37 mj Ame @ l is Gayweetin comeet. sro,

2 #2 a tutum Ra ķ= 65.8 at, Rq² 46.5 , R₂ = 78.62 and Ra= 25.62 Here, R₂ 4 Rz de parallel. so, R = RR3 - 465X78.6 RotR 100 46.5 +7806 R'= 29:21 2 R Rab R = R' = 65.8+29.20. - 95 2 Now the equivalent resistance between a and to print will be Rega RqXR" - RatR" 25.6+95 & Rega 20.16 Rega 2002 option - (12 is commeet. 25.6x 95

#3. Por conductor Resistivity LCP temp (7) Con alloy Po semiconducton т- So, the resistivity of a metal material is temperature dependent. loption @ is consect.

#4. 인 G= 15.3 up = 15.3x108 Cq2 25.62f = 25.6x20 ºr = 36 4 ME= 36.4x10 of cao 62.2 xf = 62.2x100F csa 85.4 xe = 85.4×10 CF here, a la dre parallel. So, e-eetle = (15.3+62.2 x 206 &ca 77.5x256f

e , en Here, &&es are parallel. s, ca estes = (36.4+8514) xaoof &6 = 121.8 UR 212.8x10ff How , Now , new circuit is a. It it to des + = + statisxjög + és crioy + 4218xing) -) čex = 60.175 x163x106 & cega 16.6X10of leeg a 16.6 up This is the equivalent capacitance behreen A & B point.. option (a) is consect.

# 5. ve 15 volt. 8 = ceava 1664 15 -18 2249 vel So, the change of ce capaciton will be 249ree. I option (a) is comment