Question

3. In pigs, black hair (B) is dominant to red hair (b). Erect ears (E) are dominant to drooping ears (e). What are the expected proportions of the different phenotypes resulting from a mating between two pigs heterozygous for both traits? SHOW A PUNNETT SQUARE 4. There are 2 colors in color squash, white & yellow. White (W) is dominant over yellow (w). What are the expected genotype and phenotype frequencies for each of the following crosses? a. Ww xww b. WW x Ww c. Ww X WW d. Ww x Ww 5. In mice black and white coats are an example of incomplete dominance. Heterozygotes are grey. A grey mouse is mated to a white mouse. What are the genotypes and phenotypes of parents and offspring? Show the results in a Punnett square for full credit.6. A man with normal vision sues his wife, who also has normal vision, for divorce on grounds of infidelity. Their daughter is colorblind. Does the genetic evidence support the man's case? Explain.

that's all the professor give

Answer 1

3. In pigs black hair colour is dominant to red and erect ear is dominant to drooping ear. So a heterozygous pig will have BbEe genotype . The punnett square is shown below:-The ratio of phenotype is= 9(black hair and erect ear): 3(black hair and drooping ear): 3( red hair and erect ear):1( red hair and drooping ear).

4 a) Ratio of both genotype and phenotype is 1: 1

b)c)

d)

5. Grey mice is heterozygous so it's genotype is Bb and white is recessive so it's genotype is bb. Their cross is shown below:-ratio of genotype is 1:1

Ratio of phenotype is 1 (grey): 1(white)

6. Yes, the genetic evidence supports man's case. As colour blindness is x linked inheritance, when the man has normal vision he will have XY genotype and since the women also have normal vision se can be carrier and then her genotype will be X^cY. The cross is shown below:-we can see from the punnett square that they can have a colour blind son and a carrier daughter. They can't have a colour blind daughter.

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