Question

Balancing a Stick Due in 16 hours, 47 minutes The figure below is a long, massless stick with evenly spaced marks. The distance between two adjacent marks is 6.40 cm. In each of the following problems a pivot will be placed at a point on the stick. The pivot will hold that point fixed, but allow the stick to rotate. You will be finding conditions that will keep the stick in static equilibrium given K B G D F C EJLH A different forces. All forces will be applied to the stick perpendicular to the length of the stick. A pivot is placed at Point D and a force of 18.0 N is directed downward perpendicular to the stick at Point A. What is the magnitude and direction of the force which must be applied at point B in order to obtain static equilibrium? Upward Downward Submit Answer Tries 0/10 A pivot is placed at Point K and a force of 36.0 N is directed downward perpendicular to the stick at Point L. What is the magnitude and direction of the force which must be applied at point C in order to obtain static equilibrium? Upward Downward Submit Answer Tries 0/10 A pivot is placed at Point E and a force of 37.0 N is directed downward perpendicular to the stick at Point A. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If the is no point that will work within reason, select the option None A force of 74.0 N directed downward perpendicular to the stick. A force of 16.4 N directed upward perpendicular to the stick. A force of 49.3 N directed upward perpendicular to the stick. Submit Answer Tries 0/10
help

Answer 1

Please do not post these many questions at once....the concept is same in all og them.

1) Equating the torque, we get

-18*7*0.0640 = F * 0.128

-8.064 = F * 0.128

F = 63 N (downward)

2) -36*8*0.0640 = -F*5*0.0640

F = 57.6 N (upward)

3) (i) L = 37*4*0.0640 / 74

L = 0.128

Therefore, it should be at point F acting downwards

(ii) none

(iii) at D