Question

The figure below is a long, massless stick with evenly spaced marks. The distance between two adjacent marks is 10.10 cm. In each of the following problems a pivot will be placed at a point on the stick. The pivot will hold that point fixed, but allow the stick to rotate. You will be finding conditions that will keep the stick in static equilibrium given different forces. All forces will be applied to the stick perpendicular to the length G D L E J B H K 1 C 1 1 1 d of the stick. A pivot is placed at Point A and a force of 35.0 N is directed downward perpendicular to the stick at Point C. What is the magnitude and direction of the force which must be applied at point Lin order to obtain static equilibrium? 10.10 N Upward Downward Submit Answer Incorrect. Tries 2/10 Previous Tries A pivot placed at Point D and a force of 11.0 N is directed downward perpendicular to the stick at Point F. What is the magnitude and direction the force which must be applied point C in order to obtain static equilibrium? Upward Downward Submit Answer Tries 0/10 A pivot is placed at Point K and a force of 20.0 N is directed downward perpendicular to the stick at Point C. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If the is no point that will work within reason, select the option None. A force of 20.0 N directed downward perpendicular to the stick. A force of 16.0 N directed upward perpendicular to the stick. A force of 8.0 N directed upward perpendicular to the stick. Submit Answer Tries 0/10

Answer 1

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Distanne Wow how adjacent mašks is 10.106m [ 0.101m) GDLCJKA BHF Divot at a Too stakic equillibaium Zonet = 0 consider upward force -ve' and downward tvel The th = 0 (Fcxd )+ (oflade) = 0 (35x3.303) + (FLX0-400)=0 [de=dx3, de = uxd] ELE -(350.303) Te = -26-250 Direction of force in upward. .-10.605 o nou ouou pivot al Dihet The 0.808 0.803 Pivot at ki The C (EEx df) + (Fexde) (11% 0.909)+(Fc *0.808)-o [dp=9d, de8d] Fei (11*0.909).-9.999 Fc =-12.375 Direction of the force is upward. + T=0 [2 is torque due to unknown force Force applied at is down word, so to get equillibrium upward force is needed. But in the first op lion force applied is downward. so fisst not correct. second option! F--16N (Fexde) +(FXD) = 0 (aox o.uou) +(-16xD) 20x 0.404 0:505m 16 D: 5 x 0.101 Dis equal to the distance blo pivot to point option too is correct option three option is D- sdm Cn. SO F:-8N 1.01 D: 20XO. 404 3 equal to TOYOTDizlod iod which not possible Diy because there is only segment maximum for Prvot K both sides, third option is not consect 5 cm