Question

Demand Function for Sports Watches The demand function for the Sicard sports watch is given by 10 d) - (05x520) 0.01 - 1 where x (measured in units of a thousand) is the quantity demanded per week and dow) is the unit price in dollars. (a) Find x) d') (b) Find the following values in dollars per thousand watches. (Round your answers to two decimal places.) 015) - per thousand watches (10) - per thousand watches 014) - per thousand watches Interpret the results. (Round your answers to two decibal places.) When the demand for watches is 5,000, the unit price for the watches is decreasing by $ per thousand watches. When the demand for watches is 10,000, the unit price for the watches is decreasing by per thousand watches. When the demand for watches is 14,000, the unit price for the watches is decreasing by per thousand watches Need Help?

Answer 1

d(x)= 40 0.01x?+1 x thousand of units "(°<x< 20) (a) d'(x)=d dx (40(sook'to)") - 40(0.01x+1)? (0.01x?+1) d') 0.88 01x?+12 d'(5) - 2:56 per thousand welches d'(10) = -2 -0.8(5) (6.01(25) tije 0.8 (10) (0.01(100) +)? -0.8(14) (0-01(197)+1) per thourand Watches d'(14) = $ -1.28 per thousand watches

when the demand for watches is 5,000, the unit price for the watches is decreased by $ 2.56 per thousand watches.when the demand for watches is 10,000, the unit price for the watches is decreased by $ 2 per thousand watches.when the demand for watches is 14,000, the unit price for the watches is decreased by $ 1.28 per thousand watches.